A remarkable formula by Srinivasa Ramanujan
π 2 e x x = 1 x + 1 1 + 2 x + 3 1 + 4 x + 5 1 + 6 x + 7 ⋱ + { 1 + x 1 · 3 + x2 1 · 3 · 5 + x3 1 · 3 · 5 · 7 + … } , x > 0
Last modified: 2012-09-25 10:37:46